sebanyak 25 ml larutan asam format HCOOH 0,02 M. Tentukan pH larutan asam format tersebut bila harga ka asam format = 2 x 10-4
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HCOOH merupakan asam lemah dan KOH merupakan basa kuat.
Menghitung mol asam dan basa:
table attributes columnalign right center left columnspacing 0px end attributes row cell n space H C O O H end cell equals cell 0 comma 020 space M cross times 25 space mL end cell row blank equals cell 0 comma 5 space mmol end cell row cell n space K O H end cell equals cell 0 comma 01 space M cross times 25 space mL end cell row blank equals cell 0 comma 25 space mmol end cell end table
Membuat reaksi setimbang:
tersisa asam lemah dan garam, maka larutan membentuk larutan penyangga.
table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell Ka cross times fraction numerator mol space asam space lemah over denominator mol space basa space konjugasi end fraction end cell row blank equals cell 2 cross times 10 to the power of negative sign 4 end exponent cross times fraction numerator 0 comma 25 space mmol over denominator 0 comma 25 space mmol end fraction end cell row blank equals cell 2 cross times 10 to the power of negative sign 4 end exponent end cell row blank blank blank row pH equals cell negative sign log space 2 cross times 10 to the power of negative sign 4 end exponent end cell row blank equals cell 4 minus sign log space 2 end cell end table
Dengan demikian, pH larutan setelah dititrasi dengan 25 ml KOH adalah 4 minus sign log space 2.
SEMOGA MEMUASKAN^^
#BELAJARKIMIA
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